Lab 1: Booting a PC

  • Handed out: Thursday, Mar 29, 2022.

  • Due: 11:59 pm, Friday, Apr 15, 2022.


This lab is split into three parts. The first part concentrates on getting familiarized with x86 assembly language, the QEMU x86 emulator, and the PC’s power-on bootstrap procedure. The second part examines the boot loader for our kernel, which resides in the boot/ directory of the jos/ tree. Finally, the third part delves into the initial template for our kernel itself, named JOS, which resides in the kernel/ directory.

Software Setup

The files you will need for this and subsequent lab assignments in this course are distributed using the Git version control system. To learn more about Git, take a look at the Git user’s manual, or, if you are already familiar with other version control systems, you may find this CS-oriented overview of Git useful.

You can access the repository via the course GitLab server, and you can start with forking this repository to your own namespace.

$ git clone
Cloning into jos...
$ cd jos
$ git checkout lab1

Git allows you to keep track of the changes you make to the code. For example, if you are finished with one of the exercises, and want to checkpoint your progress, you can commit your changes by running:

$ git commit -am 'my solution for lab1 exercise 9'
Created commit 60d2135: my solution for lab1 exercise 9
 1 files changed, 1 insertions(+), 0 deletions(-)

This commit will store your progress locally. If you would like to store that in our GitLab server, you may do push by running:

$ git push
Counting objects: 3, done.
Delta compression using up to 24 threads.
Compressing objects: 100% (2/2), done.
Writing objects: 100% (3/3), 269 bytes | 269.00 KiB/s, done.
Total 3 (delta 1), reused 0 (delta 0)
   a56269d..da4c4ea  lab1 -> lab1

You can keep track of your changes by using the git diff command. Running git diff will display the changes to your code since your last commit, and git diff origin/lab1 will display the changes relative to the initial code supplied for this lab. Here, origin/lab1 is the name of the git branch with the initial code you downloaded from our server for this assignment.

In case you do not use OSU’s servers

Please install qemu and possibly gcc following the directions on the tools page. Please follow the directions on the tools page as it includes several useful debugging changes to qemu and some of the later labs depend on these patches, so you must build your own. If your machine uses a native ELF toolchain (such as Linux and most BSD’s, but notably not OS X), you can simply install gcc from your package manager.

Hand-In Procedure

You will turn in your assignments by pushing your progress to the repository and tag the final version of the lab.

Before submit your lab assignment, you can run make grade to test your solutions with the grading program.

After checking your score from running make grade, which will run an autograder script (the score shown is not guaranteed, but failure to pass make grade will not get the score; score will be finalized after checking your pushed sourcecode), you can tag your commit as lab1-final and push those commits and tags to the repository to submit your progress.

$ git tag lab1-final
$ git push
$ git push origin --tags

# if you want to change the final tag,
$ git tag -d lab1-final # this will delete an existing tag
Deleted tag 'lab1-final' (was 75411c7)

$ git tag lab1-final
$ git push
$ git push origin --tags


In this lab, you may want to read the following files:















And, you must write your code to the following files:

lib/printfmt.c; vprintfmt() (for %o, the octet part)

kern/kdebug.c; debuginfo_eip()

kern/monitor.c; commands[] and mon_backtrace()

Part 1: PC Bootstrap

The purpose of the first exercise is to introduce you to x86 assembly language and the PC bootstrap process, and to get you started with QEMU and QEMU/GDB debugging. You will not have to write any code for this part of the lab, but you should go through it anyway for your own understanding and be prepared to answer the questions posed below.

Getting Started with x86 assembly

If you are not already familiar with x86 assembly language, you will quickly become familiar with it during this course! The PC Assembly Language Book is an excellent place to start. Hopefully, the book contains mixture of new and old material for you.

Warning: Unfortunately the examples in the book are written for the NASM assembler, whereas we will be using the GNU assembler. NASM uses the so-called Intel syntax while GNU uses the AT&T syntax. While semantically equivalent, an assembly file will differ quite a lot, at least superficially, depending on which syntax is used. Luckily the conversion between the two is pretty simple, and is covered in Brennan’s Guide to Inline Assembly.


Exercise 1. Familiarize yourself with the assembly language materials available on the cs444 reference page. You don’t have to read them now, but you’ll almost certainly want to refer to some of this material when reading and writing x86 assembly.

We do recommend reading the section “The Syntax” in Brennan’s Guide to Inline Assembly. It gives a good (and quite brief) description of the AT&T assembly syntax we’ll be using with the GNU assembler in JOS.

Certainly the definitive reference for x86 assembly language programming is Intel’s instruction set architecture reference, which you can find on the cs444/544 reference page in two flavors: an HTML edition of the old 80386 Programmer’s Reference Manual, which is much shorter and easier to navigate than more recent manuals but describes all of the x86 processor features that we will make use of in cs444/544; and the full, latest and greatest IA-32 Intel Architecture Software Developer’s Manuals from Intel, covering all the features of the most recent processors that we won’t need in class but you may be interested in learning about. An equivalent (and often friendlier) set of manuals is available from AMD. Save the Intel/AMD architecture manuals for later or use them for reference when you want to look up the definitive explanation of a particular processor feature or instruction.

Simulating the x86

Instead of developing the operating system on a real, physical personal computer (PC), we use a program that faithfully emulates a complete PC: the code you write for the emulator will boot on a real PC and you will be asked to test in the recitation. Using an emulator simplifies debugging; you can, for example, set break points inside of the emulated x86, which is difficult to do with the silicon version of an x86.

In cs444/544, we will use the QEMU Emulator, a modern and relatively fast emulator. While QEMU’s built-in monitor provides only limited debugging support, QEMU can act as a remote debugging target for the GNU debugger (GDB), which we’ll use in this lab to step through the early boot process.

To get started, clone the Lab 1 repo into your own directory as described above in “Software Setup”, then type make (or gmake on BSD systems) in the jos/ directory to build the minimal cs444/544 boot loader and kernel you will start with. (It’s a little generous to call the code we’re running here a “kernel,” but we’ll flesh it out throughout the semester.)

$ cd jos
$ make
+ as kern/entry.S
+ cc kern/init.c
+ cc kern/console.c
+ cc kern/monitor.c
+ cc kern/printf.c
+ cc lib/printfmt.c
+ cc lib/readline.c
+ cc lib/string.c
+ ld obj/kern/kernel
+ as boot/boot.S
+ cc -Os boot/main.c
+ ld boot/boot
boot block is 414 bytes (max 510)
+ mk obj/kern/kernel.img


In case if you are working on your own machine (not on the servers) and if you get errors like “undefined reference to __udivdi3”, you probably don’t have the 32-bit gcc multilib. If you’re running Debian or Ubuntu, try installing the gcc-multilib package.

$ sudo apt-get install gcc-multilib

Now you’re ready to run QEMU, supplying the file obj/kern/kernel.img, created above, as the contents of the emulated PC’s “virtual hard disk.” This hard disk image contains both our boot loader (obj/boot/boot) and our kernel (obj/kernel).

$ make qemu-nox

This executes QEMU with the options required to set the hard disk and direct serial port output to the terminal. Some text should appear in the QEMU window:

$ make qemu-nox
*** Use Ctrl-a x to exit qemu
qemu-system-i386 -nographic -drive file=obj/kern/kernel.img,index=0,media=disk,format=raw -serial mon:stdio -gdb tcp::26003 -D qemu.log
444544 decimal is XXX octal!
entering test_backtrace 5
entering test_backtrace 4
entering test_backtrace 3
entering test_backtrace 2
entering test_backtrace 1
entering test_backtrace 0
leaving test_backtrace 0
leaving test_backtrace 1
leaving test_backtrace 2
leaving test_backtrace 3
leaving test_backtrace 4
leaving test_backtrace 5
Welcome to the JOS kernel monitor!
Type 'help' for a list of commands.

Everything after “Booting from Hard Disk…” was printed by our skeletal JOS kernel; the K> is the prompt printed by the small monitor, or interactive control program, that we’ve included in the kernel. These lines printed by the kernel will also appear in the regular shell window from which you ran QEMU. This is because for testing and lab grading purposes we have set up the JOS kernel to write its console output not only to the virtual VGA display (as seen in the QEMU window), but also to the simulated PC’s virtual serial port, which QEMU in turn outputs to its own standard output. Likewise, the JOS kernel will take input from both the keyboard and the serial port, so you can give it commands in either the VGA display window or the terminal running QEMU. Alternatively, you can use the serial console without the virtual VGA by running make qemu-nox. This may be convenient if you are SSH’d into a remote server.

There are only two commands you can give to the kernel monitor, help and kerninfo (info-kern in some versions of QEMU).

K> help
help - display this list of commands
kerninfo - display information about the kernel
K> kerninfo
Special kernel symbols:
  entry  f010000c (virt)  0010000c (phys)
  etext  f0101a75 (virt)  00101a75 (phys)
  edata  f0112300 (virt)  00112300 (phys)
  end    f0112960 (virt)  00112960 (phys)
Kernel executable memory footprint: 75KB

The help command is obvious, and we will shortly discuss the meaning of what the kerninfo command prints. Although simple, it’s important to note that this kernel monitor is running “directly” on the “raw (virtual) hardware” of the simulated PC. This means that you should be able to copy the contents of obj/kern/kernel.img onto the first few sectors of a real hard disk, insert that hard disk into a real PC, turn it on, and see exactly the same thing on the PC’s real screen as you did above in the QEMU window. (We don’t recommend you do this on a real machine with useful information on its hard disk, though, because copying kernel.img onto the beginning of its hard disk will trash the master boot record and the beginning of the first partition, effectively causing everything previously on the hard disk to be lost!)

The PC’s Physical Address Space

We will now dive into a bit more detail about how a PC starts up. A PC’s physical address space is hard-wired to have the following general layout:

+------------------+  <- 0xFFFFFFFF (4GB)
|      32-bit      |
|  memory mapped   |
|     devices      |
|                  |

|                  |
|      Unused      |
|                  |
+------------------+  <- depends on amount of RAM
|                  |
|                  |
| Extended Memory  |
|                  |
|                  |
+------------------+  <- 0x00100000 (1MB)
|     BIOS ROM     |
+------------------+  <- 0x000F0000 (960KB)
|  16-bit devices, |
|  expansion ROMs  |
+------------------+  <- 0x000C0000 (768KB)
|   VGA Display    |
+------------------+  <- 0x000A0000 (640KB)
|                  |
|    Low Memory    |
|                  |
+------------------+  <- 0x00000000

The first PCs, which were based on the 16-bit Intel 8088 processor, were only capable of addressing 1MB of physical memory. The physical address space of an early PC would therefore start at 0x00000000 but end at 0x000FFFFF instead of 0xFFFFFFFF. The 640KB area marked “Low Memory” was the only random-access memory (RAM) that an early PC could use; in fact the very earliest PCs only could be configured with 16KB, 32KB, or 64KB of RAM!

The 384KB area from 0x000A0000 through 0x000FFFFF was reserved by the hardware for special uses such as video display buffers and firmware held in non-volatile memory. The most important part of this reserved area is the Basic Input/Output System (BIOS), which occupies the 64KB region from 0x000F0000 through 0x000FFFFF. In early PCs the BIOS was held in true read-only memory (ROM), but current PCs store the BIOS in updateable flash memory. The BIOS is responsible for performing basic system initialization such as activating the video card and checking the amount of memory installed. After performing this initialization, the BIOS loads the operating system from some appropriate location such as floppy disk, hard disk, CD-ROM, or the network, and passes control of the machine to the operating system.

When Intel finally “broke the one megabyte barrier” with the 80286 and 80386 processors, which supported 16MB and 4GB physical address spaces respectively, the PC architects nevertheless preserved the original layout for the low 1MB of physical address space in order to ensure backward compatibility with existing software. Modern PCs therefore have a “hole” in physical memory from 0x000A0000 to 0x00100000, dividing RAM into “low” or “conventional memory” (the first 640KB) and “extended memory” (everything else). In addition, some space at the very top of the PC’s 32-bit physical address space, above all physical RAM, is now commonly reserved by the BIOS for use by 32-bit PCI devices.

Recent x86 processors can support more than 4GB of physical RAM, so RAM can extend further above 0xFFFFFFFF. In this case the BIOS must arrange to leave a second hole in the system’s RAM at the top of the 32-bit addressable region, to leave room for these 32-bit devices to be mapped. Because of design limitations JOS will use only the first 256MB of a PC’s physical memory anyway, so for now we will pretend that all PCs have “only” a 32-bit physical address space. But dealing with complicated physical address spaces and other aspects of hardware organization that evolved over many years is one of the important practical challenges of OS development.


In this portion of the lab, you’ll use QEMU’s debugging facilities to investigate how an IA-32 compatible computer boots.

Open two terminal windows. In one, enter make qemu-nox-gdb. This starts up QEMU, but QEMU stops just before the processor executes the first instruction and waits for a debugging connection from GDB. In the second terminal, from the same directory, run gdb. You should see something like this,

$ gdb
+ target remote localhost:26003
warning: No executable has been specified and target does not support
determining executable automatically.  Try using the "file" command.
warning: A handler for the OS ABI "GNU/Linux" is not built into this configuration
of GDB.  Attempting to continue with the default i8086 settings.

The target architecture is assumed to be i8086
[f000:fff0]    0xffff0: ljmp   $0xf000,$0xe05b
0x0000fff0 in ?? ()
+ symbol-file obj/kern/kernel

We provided a .gdbinit file that set up GDB to debug the 16-bit code used during early boot and directed it to attach to the listening QEMU.

(If it doesn’t work, you may have to add an add-auto-load-safe-path=$JOS_PATH/.gdbinit in your .gdbinit file in the home directory. This is to convince gdb to process the .gdbinit we have provided. Substitute $JOS_PATH with the JOS source code path from where you are running the gdb. gdb will tell you if you have to add add-auto-load-safe-path.)

The following line:

[f000:fff0] 0xffff0:    ljmp   $0xf000,$0xe05b

is GDB’s disassembly of the first instruction to be executed. From this output you can conclude a few things:

  • The IBM PC starts executing at physical address 0x000ffff0, which is at the very top of the 64KB area reserved for the ROM BIOS.

  • The PC starts executing with CS = 0xf000 and IP = 0xfff0.

  • The first instruction to be executed is a jmp instruction, which jumps to the segmented address CS = 0xf000 and IP = 0xe05b.

Why does QEMU start like this? This is how Intel designed the 8088 processor, which IBM used in their original PC. Because the BIOS in a PC is “hard-wired” to the physical address range 0x000f0000-0x000fffff, this design ensures that the BIOS always gets control of the machine first after power-up or any system restart - which is crucial because on power-up there is no other software anywhere in the machine’s RAM that the processor could execute. The QEMU emulator comes with its own BIOS, which it places at this location in the processor’s simulated physical address space. On processor reset, the (simulated) processor enters real mode and sets CS to 0xf000 and the IP to 0xfff0, so that execution begins at that (CS:IP) segment address. How does the segmented address 0xf000:0xfff0 turn into a physical address?

To answer that we need to know a bit about real mode addressing. In real mode (the mode that PC starts off in), address translation works according to the formula:

\(physical\ address = 16 \times segment + offset\)

So, when the PC sets CS to 0xf000 and IP to 0xfff0, the physical address referenced is:

16 * 0xf000 + 0xfff0   # in hex multiplication by 16 is
= 0xf0000 + 0xfff0     # easy--just append a 0.
= 0xffff0

0xffff0 is 16 bytes before the end of the BIOS (0x100000). Therefore we shouldn’t be surprised that the first thing that the BIOS does is jmp backwards to an earlier location in the BIOS; after all how much could it accomplish in just 16 bytes?


Exercise 2. Use GDB’s si (Step Instruction) command to trace into the ROM BIOS for a few more instructions, and try to guess what it might be doing. You might want to look at Phil Storrs and his I/O Ports Description, as well as other materials on the cs444/544 reference materials page. No need to figure out all the details - just the general idea of what the BIOS is doing first.

When the BIOS runs, it sets up an interrupt descriptor table and initializes various devices such as the VGA display. This is where the “Starting SeaBIOS” message you see in the QEMU window comes from.

After initializing the PCI bus and all the important devices the BIOS knows about, it searches for a bootable device such as a floppy, hard drive, or CD-ROM. Eventually, when it finds a bootable disk, the BIOS reads the boot loader from the disk and transfers control to it.

Part 2: The Boot Loader

Floppy and hard disks for PCs are divided into 512 byte regions called sectors. A sector is the disk’s minimum transfer granularity: each read or write operation must be one or more sectors in size and aligned on a sector boundary. If the disk is bootable, the first sector is called the boot sector, since this is where the boot loader code resides. When the BIOS finds a bootable floppy or hard disk, it loads the 512-byte boot sector into memory at physical addresses 0x7c00 through 0x7dff, and then uses a jmp instruction to set the CS:IP to 0000:7c00, passing control to the boot loader. Like the BIOS load address, these addresses are fairly arbitrary - but they are fixed and standardized for PCs. If you are curious, see how SeaBIOS actually handles this booting procedure (seabios/src/boot.c).

The ability to boot from a CD-ROM came much later during the evolution of the PC, and as a result the PC architects took the opportunity to rethink the boot process slightly. As a result, the way a modern BIOS boots from a CD-ROM is a bit more complicated (and more powerful). CD-ROMs use a sector size of 2048 bytes instead of 512, and the BIOS can load a much larger boot image from the disk into memory (not just one sector) before transferring control to it. For more information, see the “El Torito” Bootable CD-ROM Format Specification.

For cs444/544 however, we will use the conventional hard drive boot mechanism, which means that our boot loader must fit into a measly 512 bytes. The boot loader consists of one assembly language source file, boot/boot.S, and one C source file, boot/main.c. Look through these source files carefully and make sure you understand what’s going on. The boot loader must perform two main functions:

  1. First, the boot loader switches the processor from real mode to 32-bit protected mode, because it is only in this mode that software can access all the memory above 1MB in the processor’s physical address space. Protected mode is described briefly in sections 1.2.7 and 1.2.8 of PC Assembly Language, and in great detail in the Intel architecture manuals. At this point you only have to understand that translation of segmented addresses (segment:offset pairs) into physical addresses happens differently in protected mode, and that after the transition offsets are 32 bits instead of 16 bits.

  2. Second, the boot loader reads the kernel from the hard disk by directly accessing the IDE disk device registers via the x86’s special I/O instructions. If you would like to understand better what the particular I/O instructions here mean, check out the “IDE hard drive controller” section on the reference page. You will not need to learn much about programming specific devices in this class: writing device drivers is in practice a very important part of OS development, but from a conceptual or architectural viewpoint it is also one of the least interesting.

After you understand the boot loader source code, look at the file obj/boot/boot.asm. This file is a disassembly of the boot loader that our Makefile creates after compiling the boot loader. This disassembly file makes it easy to see exactly where in physical memory all of the boot loader’s code resides, and makes it easier to track what’s happening while stepping through the boot loader in GDB. Likewise, obj/kern/kernel.asm contains a disassembly of the JOS kernel, which can often be useful for debugging.

You can set address breakpoints in GDB with the b command. For example, b *0x7c00 sets a breakpoint at address 0x7C00. Once at a breakpoint, you can continue execution using the c and si commands: c causes QEMU to continue execution until the next breakpoint (or until you press Ctrl-C in GDB), and si N steps through the instructions N at a time.

To examine instructions in memory (besides the immediate next one to be executed, which GDB prints automatically), you use the x/i command. This command has the syntax x/Ni ADDR, where N is the number of consecutive instructions to disassemble and ADDR is the memory address at which to start disassembling.


Exercise 3. Take a look at the lab tools guide, especially the section on GDB commands. Even if you’re familiar with GDB, this includes some esoteric GDB commands that are useful for OS work.

Set a breakpoint at address 0x7c00, which is where the boot sector will be loaded. Continue execution until that breakpoint. Trace through the code in boot/boot.S, using the source code and the disassembly file obj/boot/boot.asm to keep track of where you are. Also use the x/i command in GDB to disassemble sequences of instructions in the boot loader, and compare the original boot loader source code with both the disassembly in obj/boot/boot.asm and GDB.

Trace into bootmain() in boot/main.c, and then into readsect(). Identify the exact assembly instructions that correspond to each of the statements in readsect(). Trace through the rest of readsect() and back out into bootmain(), and identify the begin and end of the for loop that reads the remaining sectors of the kernel from the disk. Find out what code will run when the loop is finished, set a breakpoint there, and continue to that breakpoint. Then step through the remainder of the boot loader.

Be able to answer the following questions:

  • At what point does the processor start executing 32-bit code? What exactly causes the switch from 16- to 32-bit mode?

  • What is the last instruction of the boot loader executed, and what is the first instruction of the kernel it just loaded?

  • Where is the first instruction of the kernel?

  • How does the boot loader decide how many sectors it must read in order to fetch the entire kernel from disk? Where does it find this information?

Loading the Kernel

We will now look in further detail at the C language portion of the boot loader, in boot/main.c. But before doing so, this is a good time to stop and review some of the basics of C programming.


Exercise 4. Read about programming with pointers in C.

Download the code for pointers.c, run it, and make sure you understand where all of the printed values come from. In particular, make sure you understand where the pointer addresses in lines 1 and 6 come from, how all the values in lines 2 through 4 get there, and why the values printed in line 5 are seemingly corrupted.

There are other references on pointers in C (e.g., A tutorial by Ted Jensen that cites K&R heavily), though not as strongly recommended.


Unless you are already thoroughly versed in C, do not skip or even skim this reading exercise. If you do not really understand pointers in C, you will suffer untold pain and misery in subsequent labs, and then eventually come to understand them the hard way. Trust us; you don’t want to find out what “the hard way” is.

To make sense out of boot/main.c you’ll need to know what an ELF binary is. When you compile and link a C program such as the JOS kernel, the compiler transforms each C source (.c) file into an object (.o) file containing assembly language instructions encoded in the binary format expected by the hardware. The linker then combines all of the compiled object files into a single binary image such as obj/kern/kernel, which in this case is a binary in the ELF format, which stands for “Executable and Linkable Format”.

Full information about this format is available in the ELF specification on the reference page, but you will not need to delve very deeply into the details of this format in this class. Although as a whole the format is quite powerful and complex, most of the complex parts are for supporting dynamic loading of shared libraries, which we will not do in this class. The Wikipedia page has a short description.

For purposes of cs444/544, you can consider an ELF executable to be a header with loading information, followed by several program sections, each of which is a contiguous chunk of code or data intended to be loaded into memory at a specified address. The boot loader does not modify the code or data; it loads it into memory and starts executing it.

An ELF binary starts with a fixed-length ELF header, followed by a variable-length program header listing each of the program sections to be loaded. The C definitions for these ELF headers are in inc/elf.h. The program sections we’re interested in are:

  • .text: The program’s executable instructions.

  • .rodata: Read-only data, such as ASCII string constants produced by the C compiler. (We will not bother setting up the hardware to prohibit writing, however.)

  • .data: The data section holds the program’s initialized data, such as global variables declared with initializers like int x = 5;.

When the linker computes the memory layout of a program, it reserves space for uninitialized global variables, such as int x;, in a section called .bss that immediately follows .data in memory. C requires that “uninitialized” global variables start with a value of zero. Thus there is no need to store contents for .bss in the ELF binary; instead, the linker records just the address and size of the .bss section. The loader or the program itself must arrange to zero the .bss section.

Examine the full list of the names, sizes, and link addresses of all the sections in the kernel executable by typing:

$ objdump -h obj/kern/kernel

obj/kern/kernel:     file format elf32-i386

Idx Name          Size      VMA       LMA       File off  Algn
  0 .text         00001861  f0100000  00100000  00001000  2**4
  1 .rodata       00000714  f0101880  00101880  00002880  2**5
  4 .data         0000a300  f0108000  00108000  00009000  2**12
                  CONTENTS, ALLOC, LOAD, DATA
  5 .bss          00000644  f0112300  00112300  00013300  2**5

You will see many more sections than the ones we listed above, but the others are not important for our purposes. Most of the others are to hold debugging information, which is typically included in the program’s executable file but not loaded into memory by the program loader.

Take particular note of the “VMA” (or link address) and the “LMA” (or load address) of the .text section. The load address of a section is the memory address at which that section should be loaded into memory.

The link address of a section is the memory address from which the section expects to execute. The linker encodes the link address in the binary in various ways, such as when the code needs the address of a global variable, with the result that a binary usually won’t work if it is executing from an address that it is not linked for. (It is possible to generate position-independent code that does not contain any such absolute addresses. This is used extensively by modern shared libraries, but it has performance and complexity costs, so we won’t be using it in cs444/544.)

Typically, the link and load addresses are the same. For example, look at the .text section of the boot loader:

$ objdump -h obj/boot/boot.out

obj/boot/boot.out:     file format elf32-i386

Idx Name          Size      VMA       LMA       File off  Algn
  0 .text         00000186  00007c00  00007c00  00000074  2**2
                  CONTENTS, ALLOC, LOAD, CODE

The boot loader uses the ELF program headers to decide how to load the sections. The program headers specify which parts of the ELF object to load into memory and the destination address each should occupy. You can inspect the program headers by typing:

$ objdump -x obj/kern/kernel

obj/kern/kernel:     file format elf32-i386
architecture: i386, flags 0x00000112:
start address 0x0010000c

Program Header:
    LOAD off    0x00001000 vaddr 0xf0100000 paddr 0x00100000 align 2**12
         filesz 0x00007108 memsz 0x00007108 flags r-x
    LOAD off    0x00009000 vaddr 0xf0108000 paddr 0x00108000 align 2**12
         filesz 0x0000a300 memsz 0x0000a944 flags rw-
   STACK off    0x00000000 vaddr 0x00000000 paddr 0x00000000 align 2**4
         filesz 0x00000000 memsz 0x00000000 flags rwx

The program headers are then listed under “Program Headers” in the output of objdump. The areas of the ELF object that need to be loaded into memory are those that are marked as “LOAD”. Other information for each program header is given, such as the virtual address (“vaddr”), the physical address (“paddr”), and the size of the loaded area (“memsz” and “filesz”).

Back in boot/main.c, the ph->p_pa field of each program header contains the segment’s destination physical address (in this case, it really is a physical address, though the ELF specification is vague on the actual meaning of this field).

The BIOS loads the boot sector into memory starting at address 0x7c00, so this is the boot sector’s load address. This is also where the boot sector executes from, so this is also its link address. We set the link address by passing -Ttext 0x7C00 to the linker in boot/Makefrag, so the linker will produce the correct memory addresses in the generated code.


Exercise 5. Trace through the first few instructions of the boot loader again and identify the first instruction that would “break” or otherwise do the wrong thing if you were to get the boot loader’s link address wrong. Then change the link address in boot/Makefrag to something wrong, run make clean, recompile the lab with make, and trace into the boot loader again to see what happens. Don’t forget to change the link address back and make clean again afterward!

Look back at the load and link addresses for the kernel. Unlike the boot loader, these two addresses aren’t the same: the kernel is telling the boot loader to load it into memory at a low address (1 megabyte), but it expects to execute from a high address. We’ll dig in to how we make this work in the next section.

Besides the section information, there is one more field in the ELF header that is important to us, named e_entry. This field holds the link address of the entry point in the program: the memory address in the program’s text section at which the program should begin executing. You can see the entry point:

$ readelf -h obj/kern/kernel
ELF Header:
  Magic:   7f 45 4c 46 01 01 01 00 00 00 00 00 00 00 00 00
  Class:                             ELF32
  Data:                              2's complement, little endian
  Version:                           1 (current)
  OS/ABI:                            UNIX - System V
  ABI Version:                       0
  Type:                              EXEC (Executable file)
  Machine:                           Intel 80386
  Version:                           0x1
  Entry point address:               0x10000c
  Start of program headers:          52 (bytes into file)
  Start of section headers:          81124 (bytes into file)
  Flags:                             0x0
  Size of this header:               52 (bytes)
  Size of program headers:           32 (bytes)
  Number of program headers:         3
  Size of section headers:           40 (bytes)
  Number of section headers:         11
  Section header string table index: 8

You should now be able to understand the minimal ELF loader in boot/main.c. It reads each section of the kernel from disk into memory at the section’s load address and then jumps to the kernel’s entry point.


Exercise 6. We can examine memory using GDB’s x command. The GDB manual has full details, but for now, it is enough to know that the command x/Nx ADDR prints N words of memory at ADDR (e.g., x/10x 0x10000c to print 10 words from 0x10000c). Warning: The size of a word is not a universal standard. In GNU assembly, a word is two bytes (the ‘w’ in xorw, which stands for word, means 2 bytes) and in GDB, a word means 4 bytes (and a giant for 8 bytes).

Reset the machine (exit QEMU/GDB and start them again). Examine the 8 words of memory at 0x00100000 at the point the BIOS enters the boot loader, and then again at the point the boot loader enters the kernel. Why are they different? What is there at the second breakpoint? (You do not really need to use QEMU to answer this question. Just think.)

Part 3: The Kernel

We will now start to examine the minimal JOS kernel in a bit more detail. (And you will finally get to write some code!). Like the boot loader, the kernel begins with some assembly language code that sets things up so that C language code can execute properly.

Using virtual memory to work around position dependence

When you inspected the boot loader’s link and load addresses above, they matched perfectly, but there was a (rather large) disparity between the kernel’s link address (as printed by objdump) and its load address. Go back and check both and make sure you can see what we’re talking about. (Linking the kernel is more complicated than the boot loader, so the link and load addresses are at the top of kern/kernel.ld.)

Operating system kernels often like to be linked and run at very high virtual address, such as 0xf0100000, in order to leave the lower part of the processor’s virtual address space for user programs to use. The reason for this arrangement will become clearer in the next lab.

Many machines don’t have any physical memory at address 0xf0100000, so we can’t count on being able to store the kernel there. Instead, we will use the processor’s memory management hardware to map virtual address 0xf0100000 (the link address at which the kernel code expects to run) to physical address 0x00100000 (where the boot loader loaded the kernel into physical memory). This way, although the kernel’s virtual address is high enough to leave plenty of address space for user processes, it will be loaded in physical memory at the 1MB point in the PC’s RAM, just above the BIOS ROM. This approach requires that the PC have at least a few megabytes of physical memory (so that physical address 0x00100000 works), but this is likely to be true of any PC built after about 1990.

In fact, in the next lab, we will map the entire bottom 256MB of the PC’s physical address space, from physical addresses 0x00000000 through 0x0fffffff, to virtual addresses 0xf0000000 through 0xffffffff respectively. You should now see why JOS can only use the first 256MB of physical memory.

For now, we’ll just map the first 4MB of physical memory, which will be enough to get us up and running. We do this using the hand-written, statically-initialized page directory and page table in kern/entrypgdir.c. For now, you don’t have to understand the details of how this works, just the effect that it accomplishes. Up until kern/entry.S sets the CR0_PG flag, memory references are treated as physical addresses (strictly speaking, they’re linear addresses, but boot/boot.S set up an identity mapping from linear addresses to physical addresses and we’re never going to change that). Once CR0_PG is set, memory references are virtual addresses that get translated by the virtual memory hardware to physical addresses. entry_pgdir translates virtual addresses in the range 0xf0000000 through 0xf0400000 to physical addresses 0x00000000 through 0x00400000, as well as virtual addresses 0x00000000 through 0x00400000 to physical addresses 0x00000000 through 0x00400000. Any virtual address that is not in one of these two ranges will cause a hardware exception which, since we haven’t set up interrupt handling yet, will cause QEMU to dump the machine state and exit.


Exercise 7. Use QEMU and GDB to trace into the JOS kernel and stop at the movl %eax, %cr0. Examine memory at 0x00100000 and at 0xf0100000. Now, single step over that instruction using the stepi GDB command. Again, examine memory at 0x00100000 and at 0xf0100000. Make sure you understand what just happened.

What is the first instruction after the new mapping is established that would fail to work properly if the mapping weren’t in place? Comment out the movl %eax, %cr0 in kern/entry.S, trace into it, and see if you were right.

Formatted Printing to the Console

Most people take functions like printf() for granted, sometimes even thinking of them as “primitives” of the C language. But in an OS kernel, we have to implement all I/O ourselves.

Read through kern/printf.c, lib/printfmt.c, and kern/console.c, and make sure you understand their relationship. It will become clear in later labs why printfmt.c is located in the separate lib/ directory.


Exercise 8. We have omitted a small fragment of code - the code necessary to print octal numbers using patterns of the form “%o”. Find and fill in this code fragment.

Be able to answer the following questions:

  1. Explain the interface between kern/printf.c and kern/console.c. Specifically, what function does kern/console.c export? How is this function used by kern/printf.c?

  2. Explain the following from kern/console.c:

1 if (crt_pos >= CRT_SIZE) {
2   int i;
3   memcpy(crt_buf, crt_buf + CRT_COLS, (CRT_SIZE - CRT_COLS) * sizeof(uint16_t));
4   for (i = CRT_SIZE - CRT_COLS; i < CRT_SIZE; i++)
5     crt_buf[i] = 0x0700 | ' ';
6   crt_pos -= CRT_COLS;
7 }
  1. For the following questions you might wish to consult the notes for Lecture 2. These notes cover GCC’s calling convention on the x86.

    Trace the execution of the following code step-by-step:

int x = 1, y = 3, z = 4;
cprintf("x %d, y %x, z %d\n", x, y, z);
  • In the call to cprintf(), to what does fmt point? To what does ap point?

  • List (in order of execution) each call to cons_putc, va_arg, and vcprintf. For cons_putc, list its argument as well. For va_arg, list what ap points to before and after the call. For vcprintf list the values of its two arguments.

  1. Run the following code.

unsigned int i = 0x00646c72;
cprintf("H%x Wo%s", 57616, &i);

What is the output? Explain how this output is arrived at in the step-by-step manner of the previous exercise. Here’s an ASCII table (or type man ascii) that maps bytes to characters.

The output depends on that fact that the x86 is little-endian. If the x86 were instead big-endian what would you set i to in order to yield the same output? Would you need to change 57616 to a different value?

Here’s a description of little- and big-endian and a more whimsical description.

  1. In the following code, what is going to be printed after 'y='? (note: the answer is not a specific value.) Why does this happen?

cprintf("x=%d y=%d", 3);
  1. Let’s say that GCC changed its calling convention so that it pushed arguments on the stack in declaration order, so that the last argument is pushed last. How would you have to change cprintf or its interface so that it would still be possible to pass it a variable number of arguments?


Challenge (Extra credit 1%). Enhance the console to allow text to be printed in different colors. The traditional way to do this is to make it interpret ANSI escape sequences embedded in the text strings printed to the console, but you may use any mechanism you like. There is plenty of information on the cs444/544 reference page and elsewhere on the web on programming the VGA display hardware. If you’re feeling really adventurous, you could try switching the VGA hardware into a graphics mode and making the console draw text onto the graphical frame buffer.

To get 1% of credit, please create a command ‘show’ in the monitor and print a beautiful ASCII Art with 5 or more colors when the command is typed on the console.

Once you finish this, please create a file .lab1-extra at the root of your repository directory (under jos/). We will use that file as an indicator that you finished this extra-credit and then grade your work accordingly.

The Stack

In the final exercise of this lab, we will explore in more detail the way the C language uses the stack on the x86, and in the process write a useful new kernel monitor function that prints a backtrace of the stack: a list of the saved Instruction Pointer (IP) values from the nested call instructions that led to the current point of execution.


Exercise 9. Determine where the kernel initializes its stack, and exactly where in memory its stack is located. How does the kernel reserve space for its stack? And at which “end” of this reserved area is the stack pointer initialized to point to?

The x86 stack pointer (esp register) points to the lowest location on the stack that is currently in use. Everything below that location in the region reserved for the stack is free. Pushing a value onto the stack involves decreasing the stack pointer and then writing the value to the place the stack pointer points to. Popping a value from the stack involves reading the value the stack pointer points to and then increasing the stack pointer. In 32-bit mode, the stack can only hold 32-bit values, and esp is always divisible by four. Various x86 instructions, such as call, are “hard-wired” to use the stack pointer register.

The ebp (base pointer) register, in contrast, is associated with the stack primarily by software convention. On entry to a C function, the function’s prologue code normally saves the previous function’s base pointer by pushing it onto the stack, and then copies the current esp value into ebp for the duration of the function. If all the functions in a program obey this convention, then at any given point during the program’s execution, it is possible to trace back through the stack by following the chain of saved ebp pointers and determining exactly what nested sequence of function calls caused this particular point in the program to be reached. This capability can be particularly useful, for example, when a particular function causes an assert failure or panic because bad arguments were passed to it, but you aren’t sure who passed the bad arguments. A stack backtrace lets you find the offending function.


Exercise 10. To become familiar with the C calling conventions on the x86, find the address of the test_backtrace` function in obj/kern/kernel.asm, set a breakpoint there, and examine what happens each time it gets called after the kernel starts. How many 32-bit words does each recursive nesting level of test_backtrace push on the stack, and what are those words? NOTE. you’ll have to manually translate all breakpoint and memory addresses to linear addresses.

The above exercise should give you the information you need to implement a stack backtrace function, which you should call mon_backtrace(). A prototype for this function is already waiting for you in kern/monitor.c. You can do it entirely in C, but you may find the read_ebp() function in inc/x86.h useful. You’ll also have to hook this new function into the kernel monitor’s command list so that it can be invoked interactively by the user.

The backtrace function should display a listing of function call frames in the following format:

Stack backtrace:
  ebp f0109e58  eip f0100a62  args 00000001 f0109e80 f0109e98 f0100ed2 00000031
  ebp f0109ed8  eip f01000d6  args 00000000 00000000 f0100058 f0109f28 00000061

The first line printed reflects the currently executing function, namely mon_backtrace itself, the second line reflects the function that called mon_backtrace, the third line reflects the function that called that one, and so on. You should print all the outstanding stack frames. By studying kern/entry.S you’ll find that there is an easy way to tell when to stop.

Within each line, the ebp value indicates the base pointer into the stack used by that function: i.e., the position of the stack pointer just after the function was entered and the function prologue code set up the base pointer. The listed eip value is the function’s return instruction pointer: the instruction address to which control will return when the function returns. The return instruction pointer typically points to the instruction after the call instruction (why?). Finally, the five hex values listed after args are the first five arguments to the function in question, which would have been pushed on the stack just before the function was called. If the function was called with fewer than five arguments, of course, then not all five of these values will be useful. (Why can’t the backtrace code detect how many arguments there actually are? How could this limitation be fixed?)

Here are a few specific points you read about in K&R Chapter 5 that are worth remembering for the following exercise and for future labs.

  • If int *p = (int*)100, then (int)p + 1 and (int)(p + 1) are different numbers: the first is 101 but the second is 104. When adding an integer to a pointer, as in the second case, the integer is implicitly multiplied by the size of the object the pointer points to.

  • p[i] is defined to be the same as *(p+i), referring to the i’th object in the memory pointed to by p. The above rule for addition helps this definition work when the objects are larger than one byte.

  • &p[i] is the same as (p+i), yielding the address of the i’th object in the memory pointed to by p.

Although most C programs never need to cast between pointers and integers, operating systems frequently do. Whenever you see an addition involving a memory address, ask yourself whether it is an integer addition or pointer addition and make sure the value being added is appropriately multiplied or not.


Exercise 11. Implement the backtrace function as specified above. Use the same format as in the example, since otherwise the grading script will be confused. When you think you have it working right, run make grade to see if its output conforms to what our grading script expects, and fix it if it doesn’t. After you have handed in your Lab 1 code, you are welcome to change the output format of the backtrace function any way you like.

If you use read_ebp(), note that GCC may generate “optimized” code that calls read_ebp() before mon_backtrace()’s function prologue, which results in an incomplete stack trace (the stack frame of the most recent function call is missing). While we have tried to disable optimizations that cause this reordering, you may want to examine the assembly of mon_backtrace() and make sure the call to read_ebp() is happening after the function prologue.

At this point, your backtrace function should give you the addresses of the function callers on the stack that lead to mon_backtrace() being executed. However, in practice you often want to know the function names corresponding to those addresses. For instance, you may want to know which functions could contain a bug that’s causing your kernel to crash.

To help you implement this functionality, we have provided the function debuginfo_eip(), which looks up eip in the symbol table and returns the debugging information for that address. This function is defined in kern/kdebug.c.


Exercise 12. Modify your stack backtrace function to display, for each eip, the function name, source file name, and line number corresponding to that eip.

In debuginfo_eip, where do __STAB_* come from? This question has a long answer; to help you to discover the answer, here are some things you might want to do:

  • look in the file kern/kernel.ld for __STAB_*

  • run objdump -h obj/kern/kernel

  • run objdump -G obj/kern/kernel

  • run gcc -pipe -nostdinc -O2 -fno-builtin -I. -MD -Wall -Wno-format -DJOS\_KERNEL -gstabs -c -S kern/init.c, and look at kern/init.s.

  • see if the bootloader loads the symbol table in memory as part of loading the kernel binary

Complete the implementation of debuginfo_eip by inserting the call to stab_binsearch to find the line number for an address.

Add a backtrace command to the kernel monitor, and extend your implementation of mon_backtrace to call debuginfo_eip and print a line for each stack frame of the form:

K> backtrace
Stack backtrace:
  ebp f010ff78  eip f01008ae  args 00000001 f010ff8c 00000000 f0110580 00000000
         kern/monitor.c:143: monitor+106
  ebp f010ffd8  eip f0100193  args 00000000 00001aac 00000660 00000000 00000000
         kern/init.c:49: i386_init+59
  ebp f010fff8  eip f010003d  args 00000000 00000000 0000ffff 10cf9a00 0000ffff
         kern/entry.S:70: <unknown>+0

Each line gives the file name and line within that file of the stack frame’s eip, followed by the name of the function and the offset of the eip from the first instruction of the function (e.g., monitor+106 means the return eip is 106 bytes past the beginning of monitor).

Be sure to print the file and function names on a separate line, to avoid confusing the grading script.


Tip printf format strings provide an easy, albeit obscure, way to print non-null-terminated strings like those in STABS tables. printf("%.*s", length, string) prints at most length characters of string. Take a look at the printf man page to find out why this works.

You may find that some functions are missing from the backtrace. For example, you will probably see a call to monitor() but not to runcmd(). This is because the compiler in-lines some function calls. Other optimizations may cause you to see unexpected line numbers. If you get rid of the -O2 from Makefile, the backtraces may make more sense (but your kernel will run more slowly).

This completes the lab. In the jos directory, commit your changes with git commit, git tag lab1-final, git push, and git push origin --tags to submit your code. Please do not forget to create and include the file .lab1-extra in case you finished extra-credit challenge.

Grading example

$ make grade
make clean
make[1]: Entering directory '/home/red9057/jos'
rm -rf obj .gdbinit qemu.log
make[1]: Leaving directory '/home/red9057/jos'
make[1]: Entering directory '/home/red9057/jos'
+ as kern/entry.S
+ cc kern/entrypgdir.c
+ cc kern/init.c
+ cc kern/console.c
+ cc kern/monitor.c
+ cc kern/printf.c
+ cc kern/kdebug.c
+ cc lib/printfmt.c
+ cc lib/readline.c
+ cc lib/string.c
+ ld obj/kern/kernel
ld: warning: section '.bss' type changed to PROGBITS
+ as boot/boot.S
+ cc -Os boot/main.c
+ ld boot/boot
boot block is 390 bytes (max 510)
+ mk obj/kern/kernel.img
make[1]: Leaving directory '/home/red9057/jos'
running JOS: (0.6s)
  printf: OK
  backtrace count: OK
  backtrace arguments: OK
  backtrace symbols: OK
  backtrace lines: OK
Score: 50/50

Sample Output You may get a different result for the address or source line numbers, however, the number of backtraces and each of function/file names must be matched.

$ make qemu-nox
*** Use Ctrl-a x to exit qemu
qemu-system-i386 -nographic -drive file=obj/kern/kernel.img,index=0,media=disk,format=raw -serial mon:stdio -gdb tcp::26003 -D qemu.log
444544 decimal is XXX octal!
entering test_backtrace 5
entering test_backtrace 4
entering test_backtrace 3
entering test_backtrace 2
entering test_backtrace 1
entering test_backtrace 0
Stack backtrace:
  ebp f010ff18  eip f0100078  args 00000000 00000000 00000000 f010004a f0111308
         kern/init.c:18: test_backtrace+56
  ebp f010ff38  eip f01000a1  args 00000000 00000001 f010ff78 f010004a f0111308
         kern/init.c:16: test_backtrace+97
  ebp f010ff58  eip f01000a1  args 00000001 00000002 f010ff98 f010004a f0111308
         kern/init.c:16: test_backtrace+97
  ebp f010ff78  eip f01000a1  args 00000002 00000003 f010ffb8 f010004a f0111308
         kern/init.c:16: test_backtrace+97
  ebp f010ff98  eip f01000a1  args 00000003 00000004 00000000 f010004a f0111308
         kern/init.c:16: test_backtrace+97
  ebp f010ffb8  eip f01000a1  args 00000004 00000005 00000000 f010004a f0111308
         kern/init.c:16: test_backtrace+97
  ebp f010ffd8  eip f01000f4  args 00000005 00001aac 00000640 00000000 00000000
         kern/init.c:39: i386_init+78
  ebp f010fff8  eip f010003e  args 00000003 00001003 00002003 00003003 00004003
         kern/entry.S:83: <unknown>+0
leaving test_backtrace 0
leaving test_backtrace 1
leaving test_backtrace 2
leaving test_backtrace 3
leaving test_backtrace 4
leaving test_backtrace 5
Welcome to the JOS kernel monitor!
Type 'help' for a list of commands.
K> help
help - Display this list of commands
kerninfo - Display information about the kernel
backtrace - Show the backtrace of the current kernel stack
K> backtrace
Stack backtrace:
  ebp f010ff58  eip f0100b1a  args 00000001 f010ff80 00000000 f0100b7e f0100b2d
         kern/monitor.c:154: monitor+332
  ebp f010ffd8  eip f0100101  args 00000000 00001aac 00000640 00000000 00000000
         kern/init.c:43: i386_init+91
  ebp f010fff8  eip f010003e  args 00000003 00001003 00002003 00003003 00004003
         kern/entry.S:83: <unknown>+0